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What is the sum of (46+47+48+\cdots+90)?

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Answer and explanation

Correct answer: 3060

This is an arithmetic sequence with first term 46, last term 90, and \(90-46+1=45\) terms. Therefore, \(S=\frac{45}{2}(46+90)=\frac{45}{2}\times136=3060\). Option 4095 is the sum from \(1\) to \(90\), so it incorrectly includes the terms from \(1\) to \(45\). Exam tip: while counting consecutive integers from one endpoint to another, always add \(1\).

Related tags

MathematicsArithmetic ProgressionConsecutive IntegersSum Of Natural NumbersSequence Series

Frequently asked questions

What is the correct answer to this question?

3060

Why is this the correct answer?

This is an arithmetic sequence with first term 46, last term 90, and \(90-46+1=45\) terms. Therefore, \(S=\frac{45}{2}(46+90)=\frac{45}{2}\times136=3060\). Option 4095 is the sum from \(1\) to \(90\), so it incorrectly includes the terms from \(1\) to \(45\). Exam tip: while counting consecutive integers from one endpoint to another, always add \(1\).

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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