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What is the sum of (1+2+3+\cdots+38)?

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Answer and explanation

Correct answer: 741

The sum of the first \\(n\\) natural numbers is \\(\frac{n(n+1)}{2}\\). Here, \\(n=38\\), so \\(\frac{38\times39}{2}=19\times39=741\\). Therefore, 741 is correct. The option 760 may result from mistakenly using 40 instead of \\(n+1=39\\). Exam tip: use \\(\frac{n(n+1)}{2}\\) for the sum from 1 to \\(n\\).

Related tags

Sequences And ProgressionsNatural NumbersSum Of N TermsArithmetic SeriesGrade 9 Mathematics

Frequently asked questions

What is the correct answer to this question?

741

Why is this the correct answer?

The sum of the first \\(n\\) natural numbers is \\(\frac{n(n+1)}{2}\\). Here, \\(n=38\\), so \\(\frac{38\times39}{2}=19\times39=741\\). Therefore, 741 is correct. The option 760 may result from mistakenly using 40 instead of \\(n+1=39\\). Exam tip: use \\(\frac{n(n+1)}{2}\\) for the sum from 1 to \\(n\\).

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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