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What is the roster form of S={x: x is an odd natural number less than 7}?

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Answer and explanation

Correct answer: S={1,3,5}

The relevant concepts are odd numbers, natural numbers, and a strict upper bound. The odd natural numbers begin 1, 3, 5, 7, and so on. Since the condition says less than 7, the value 7 must be excluded. Zero is even, not odd, and is not included under the usual positive-natural-number convention. Therefore S={1,3,5}. Options B and C include 7, while D incorrectly includes 0, so option A is correct.

Related tags

SetsOdd NumbersRoster FormCommon QuestionsCommonMathematicsClass 9 Mcq

Frequently asked questions

What is the correct answer to this question?

S={1,3,5}

Why is this the correct answer?

The relevant concepts are odd numbers, natural numbers, and a strict upper bound. The odd natural numbers begin 1, 3, 5, 7, and so on. Since the condition says less than 7, the value 7 must be excluded. Zero is even, not odd, and is not included under the usual positive-natural-number convention. Therefore S={1,3,5}. Options B and C include 7, while D incorrectly includes 0, so option A is correct.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Common Questions.

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