What is the roster form of J={x: x is an even prime number less than 10}?
Answer and explanation
Correct answer: J={2}
The defining conditions are that x must be both even and prime, and it must be less than 10. Among positive even numbers, only 2 is prime; every other even number greater than 2 is divisible by 2 and therefore composite. Since 2<10, it satisfies both conditions. Thus the roster form is J={2}. Options B and C include numbers that fail one condition, while D wrongly claims that no number qualifies.
Frequently asked questions
What is the correct answer to this question?
J={2}
Why is this the correct answer?
The defining conditions are that x must be both even and prime, and it must be less than 10. Among positive even numbers, only 2 is prime; every other even number greater than 2 is divisible by 2 and therefore composite. Since 2<10, it satisfies both conditions. Thus the roster form is J={2}. Options B and C include numbers that fail one condition, while D wrongly claims that no number qualifies.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Number Systems.
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