\( \sqrt{11-6\sqrt{2}} \) का धनात्मक सरल रूप क्या है?

What is the positive simplified form of \( \sqrt{11-6\sqrt{2}} \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(3-\sqrt{2}\)

Step 1

Concept

( \(3-\sqrt{2}\)2=9-6\sqrt{2}+2=11-6\sqrt{2} ). Choose the positive principal square root.

Step 2

Why this answer is correct

The correct answer is A. \(3-\sqrt{2}\). ( \(3-\sqrt{2}\)2=9-6\sqrt{2}+2=11-6\sqrt{2} ). Choose the positive principal square root.

Step 3

Exam Tip

( \(3-\sqrt{2}\)2=9-6\sqrt{2}+2=11-6\sqrt{2} )। धनात्मक मुख्य वर्गमूल चुनें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\( \sqrt{11-6\sqrt{2}} \) का धनात्मक सरल रूप क्या है? / What is the positive simplified form of \( \sqrt{11-6\sqrt{2}} \)?

Correct Answer: A. \(3-\sqrt{2}\). Explanation: ( \(3-\sqrt{2}\)2=9-6\sqrt{2}+2=11-6\sqrt{2} )। धनात्मक मुख्य वर्गमूल चुनें। / ( \(3-\sqrt{2}\)2=9-6\sqrt{2}+2=11-6\sqrt{2} ). Choose the positive principal square root.

Which concept should I revise for this Mathematics MCQ?

( \(3-\sqrt{2}\)2=9-6\sqrt{2}+2=11-6\sqrt{2} ). Choose the positive principal square root.

What exam hint can help solve this Mathematics question?

( \(3-\sqrt{2}\)2=9-6\sqrt{2}+2=11-6\sqrt{2} )। धनात्मक मुख्य वर्गमूल चुनें।