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What is the (n)th term of the sequence (\frac{11}{6},\frac{11}{3},\frac{11}{2},\frac{22}{3},\ldots)?
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Answer and explanation
Correct answer: (\frac{11n}{6})
Each term increases by (\frac{11}{6}), so (a_n=\frac{11n}{6}). Use a common denominator to see the pattern in fractions.
Frequently asked questions
What is the correct answer to this question?
(\frac{11n}{6})
Why is this the correct answer?
Each term increases by (\frac{11}{6}), so (a_n=\frac{11n}{6}). Use a common denominator to see the pattern in fractions.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.
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