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What is the (n)th term of the sequence (81,27,9,3,1,\ldots)?श्रेणी (81,27,9,3,1,\ldots) का (n)वां पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(81\left(\frac{1}{3}\right)^{n-1}\)\(81\left(\frac{1}{3}\right)^{n-1}\)
Each term is multiplied by \(\frac{1}{3}\), so \(a_n=81\left(\frac{1}{3}\right)^{n-1}\). Keep the first term fixed and use exponent (n-1).हर पद \(\frac{1}{3}\) गुना हो रहा है इसलिए \(a_n=81\left(\frac{1}{3}\right)^{n-1}\)। पहले पद को सुरक्षित रखकर (n-1) घात लगाएं।
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