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What is the (n)th term of the sequence \(12,6,3,\frac{3}{2},\ldots\)?श्रेणी \(12,6,3,\frac{3}{2},\ldots\) का (n)वां पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(12\left(\frac{1}{2}\right)^{n-1}\)\(12\left(\frac{1}{2}\right)^{n-1}\)
Each term is multiplied by \(\frac{1}{2}\), so \(a_n=12\left(\frac{1}{2}\right)^{n-1}\). Keep the first term separate in a geometric sequence.हर बार \(\frac{1}{2}\) से गुणा हो रहा है इसलिए \(a_n=12\left(\frac{1}{2}\right)^{n-1}\)। गुणोत्तर श्रेणी में पहला पद अलग रखें।
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