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What is the last term in ( (2x+3y)^2 )?

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Answer and explanation

Correct answer: \(9y^2\)

In the identity \((a+b)^2=a^2+2ab+b^2\), the last term is \(b^2\). Here, \(a=2x\) and \(b=3y\), so the last term is \((3y)^2=9y^2\). \(12xy\) is the middle term because \(2(2x)(3y)=12xy\). Exam tip: in a square expansion, the first and last terms are the squares of the two individual terms.

Related tags

Algebraic IdentitiesSquare Of BinomialBinomial ExpansionClass 9 Mathematics

Frequently asked questions

What is the correct answer to this question?

\(9y^2\)

Why is this the correct answer?

In the identity \((a+b)^2=a^2+2ab+b^2\), the last term is \(b^2\). Here, \(a=2x\) and \(b=3y\), so the last term is \((3y)^2=9y^2\). \(12xy\) is the middle term because \(2(2x)(3y)=12xy\). Exam tip: in a square expansion, the first and last terms are the squares of the two individual terms.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Algebraic identities.

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