\( 64x^2-1 \) का गुणनखंड रूप क्या है?
What is the factor form of \( 64x^2-1 \)?
Explanation opens after your attempt
A. ( (8x+1)(8x-1) )
Concept
(64x-2=(8x)2) and \(1=1^2\). Therefore the rule \(a^2-b^2\) applies.
Why this answer is correct
The correct answer is A. ( (8x+1)(8x-1) ). (64x-2=(8x)2) and \(1=1^2\). Therefore the rule \(a^2-b^2\) applies.
Exam Tip
(64x-2=(8x)2) और \(1=1^2\) है। इसलिए \(a^2-b^2\) का नियम लगेगा।
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