\( 64x^2-1 \) का गुणनखंड रूप क्या है?

What is the factor form of \( 64x^2-1 \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. ( (8x+1)(8x-1) )

Step 1

Concept

(64x-2=(8x)2) and \(1=1^2\). Therefore the rule \(a^2-b^2\) applies.

Step 2

Why this answer is correct

The correct answer is A. ( (8x+1)(8x-1) ). (64x-2=(8x)2) and \(1=1^2\). Therefore the rule \(a^2-b^2\) applies.

Step 3

Exam Tip

(64x-2=(8x)2) और \(1=1^2\) है। इसलिए \(a^2-b^2\) का नियम लगेगा।

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Mathematics Answer, Explanation and Revision Hints

\( 64x^2-1 \) का गुणनखंड रूप क्या है? / What is the factor form of \( 64x^2-1 \)?

Correct Answer: A. ( (8x+1)(8x-1) ). Explanation: (64x-2=(8x)2) और \(1=1^2\) है। इसलिए \(a^2-b^2\) का नियम लगेगा। / (64x-2=(8x)2) and \(1=1^2\). Therefore the rule \(a^2-b^2\) applies.

Which concept should I revise for this Mathematics MCQ?

(64x-2=(8x)2) and \(1=1^2\). Therefore the rule \(a^2-b^2\) applies.

What exam hint can help solve this Mathematics question?

(64x-2=(8x)2) और \(1=1^2\) है। इसलिए \(a^2-b^2\) का नियम लगेगा।