What is \(\frac{1}{3}\) of the sum of the first (36) natural numbers?
Answer and explanation
Correct answer: 222
The sum of the first 36 natural numbers is \(S=\frac{36\times 37}{2}=666\). Therefore, \(\frac{1}{3}\) of this sum is \(666\div 3=222\). Although 224 is close, it is not obtained by dividing 666 by 3. Exam tip: first use \(\frac{n(n+1)}{2}\) to find the sum, then apply the given fraction.
Frequently asked questions
What is the correct answer to this question?
222
Why is this the correct answer?
The sum of the first 36 natural numbers is \(S=\frac{36\times 37}{2}=666\). Therefore, \(\frac{1}{3}\) of this sum is \(666\div 3=222\). Although 224 is close, it is not obtained by dividing 666 by 3. Exam tip: first use \(\frac{n(n+1)}{2}\) to find the sum, then apply the given fraction.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
