Using \( (50+1)^2 \), what is \( 51^2 \)?
Answer and explanation
Correct answer: 2601
Using \((a+b)^2=a^2+2ab+b^2\), with \(a=50\) and \(b=1\), we get \((50+1)^2=50^2+2\times50\times1+1^2=2500+100+1=2601\). Option 2600 is close, but it misses the \(1^2\) term. Exam tip: while expanding a square, include both the middle term \(2ab\) and the final term \(b^2\).
Frequently asked questions
What is the correct answer to this question?
2601
Why is this the correct answer?
Using \((a+b)^2=a^2+2ab+b^2\), with \(a=50\) and \(b=1\), we get \((50+1)^2=50^2+2\times50\times1+1^2=2500+100+1=2601\). Option 2600 is close, but it misses the \(1^2\) term. Exam tip: while expanding a square, include both the middle term \(2ab\) and the final term \(b^2\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Algebraic identities.
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