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The (n)th term of a sequence is (a_n=3n^2-2n+5). Find (a_8).

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Answer and explanation

Correct answer: 181

Given \(a_n=3n^2-2n+5\), substitute \(n=8\): \(a_8=3(8)^2-2(8)+5=3\times64-16+5=181\). Therefore, 181 is correct. A value such as 189 can result from an error while evaluating \(8^2\) or performing the subtraction. Exam tip: evaluate the power first, then multiply, subtract, and add.

Related tags

SequencesProgressionsNth TermSubstitutionQuadratic Sequence

Frequently asked questions

What is the correct answer to this question?

181

Why is this the correct answer?

Given \(a_n=3n^2-2n+5\), substitute \(n=8\): \(a_8=3(8)^2-2(8)+5=3\times64-16+5=181\). Therefore, 181 is correct. A value such as 189 can result from an error while evaluating \(8^2\) or performing the subtraction. Exam tip: evaluate the power first, then multiply, subtract, and add.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.

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