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Subtract the sum of the first (90) natural numbers from the sum of the first (100) natural numbers. What is the result?

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Answer and explanation

Correct answer: 955

Subtracting the sum of the first 90 natural numbers from the sum of the first 100 leaves only the numbers from 91 to 100. Thus, the sum is \(91+92+\cdots+100=\frac{(91+100)\times10}{2}=955\). Therefore, option B is correct. 945 is a close distractor, but it does not use the correct average, \(95.5\), of the numbers from 91 to 100. Exam tip: In such differences, cancel the common initial terms and write the remaining range directly.

Related tags

Sequences And ProgressionsNatural NumbersSum Of N Natural NumbersArithmetic SeriesNumber Patterns

Frequently asked questions

What is the correct answer to this question?

955

Why is this the correct answer?

Subtracting the sum of the first 90 natural numbers from the sum of the first 100 leaves only the numbers from 91 to 100. Thus, the sum is \(91+92+\cdots+100=\frac{(91+100)\times10}{2}=955\). Therefore, option B is correct. 945 is a close distractor, but it does not use the correct average, \(95.5\), of the numbers from 91 to 100. Exam tip: In such differences, cancel the common initial terms and write the remaining range directly.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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