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In the sequence (19,31,43,55,\ldots), which term is (151)?

Answer and explanation

Correct answer: 12th

This is an arithmetic progression with first term \(a=19\) and common difference \(d=12\). Its \(n\)th term is \(a_n=a+(n-1)d\). Thus, \(19+(n-1)\times12=151\), so \((n-1)\times12=132\), giving \(n-1=11\) and \(n=12\). Hence, 151 is the 12th term. The 13th term would be 163, so it is not correct. Exam tip: while finding a term number, use \(n-1\) correctly in the AP formula.

Related tags

Arithmetic ProgressionSequencesNth TermCommon DifferenceClass 9 MathematicsSequences And ProgressionsMathematicsClass 9 Mcq

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