In the sequence (14,22,30,38,\ldots), which term is (126)?
Answer and explanation
Correct answer: 15th
This is an arithmetic progression with first term 14 and common difference 8. Its nth term is \(a_n=14+(n-1)\times 8\). On setting \(14+(n-1)\times 8=126\), we get \(n-1=14\), hence \(n=15\). Therefore, 126 is the 15th term. The 14th term is 118, so it is a close but incorrect option. Exam tip: while finding a term number, be careful to use \(n-1\) in the AP formula.
Frequently asked questions
What is the correct answer to this question?
15th
Why is this the correct answer?
This is an arithmetic progression with first term 14 and common difference 8. Its nth term is \(a_n=14+(n-1)\times 8\). On setting \(14+(n-1)\times 8=126\), we get \(n-1=14\), hence \(n=15\). Therefore, 126 is the 15th term. The 14th term is 118, so it is a close but incorrect option. Exam tip: while finding a term number, be careful to use \(n-1\) in the AP formula.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.
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