समांतर श्रेणी में \(a_6=31\) और \(a_{14}=79\) है। \(a_{10}\) क्या होगा?
In an arithmetic progression, \(a_6=31\) and \(a_{14}=79\). What is \(a_{10}\)?
Explanation opens after your attempt
B. (55)
Concept
The increase over eight gaps is (48), so (d=6) and (a_{10}=31+4(6)=55). \(a_{10}\) lies between the two given terms.
Why this answer is correct
The correct answer is B. (55). The increase over eight gaps is (48), so (d=6) and (a_{10}=31+4(6)=55). \(a_{10}\) lies between the two given terms.
Exam Tip
आठ अंतरों में वृद्धि (48) है, इसलिए (d=6) और (a_{10}=31+4(6)=55)। \(a_{10}\) दोनों दिए पदों के बीच आता है।
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