एक समान अंतर वाले अनुक्रम में \(a_6=41\) और \(a_{15}=104\) है। \(a_1\) क्या होगा?
In a sequence with equal differences, \(a_6=41\) and \(a_{15}=104\). What will \(a_1\) be?
Explanation opens after your attempt
C. (6)
Concept
The sum of (9) differences is (104-41=63), so the difference is (7). Thus \(a_1=41-5\times7=6\).
Why this answer is correct
The correct answer is C. (6). The sum of (9) differences is (104-41=63), so the difference is (7). Thus \(a_1=41-5\times7=6\).
Exam Tip
(9) अंतरों का योग (104-41=63) है इसलिए अंतर (7) है। \(a_1=41-5\times7=6\) होगा।
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