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If (x+y+z=6) and (xy+yz+zx=11), what is the value of (x^2+y^2+z^2)?
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Answer and explanation
Correct answer: (14)
Using ( (x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx) ), (36=x^2+y^2+z^2+22). Exam tip: apply the three-term identity directly.
Frequently asked questions
What is the correct answer to this question?
(14)
Why is this the correct answer?
Using ( (x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx) ), (36=x^2+y^2+z^2+22). Exam tip: apply the three-term identity directly.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Algebraic identities.
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