\(x^2+bx+16\) पूर्ण वर्ग हो और (b) धनात्मक हो, तो (b) क्या होगा?
If \(x^2+bx+16\) is a perfect square and (b) is positive, what is (b)?
Explanation opens after your attempt
Correct Answer
B. (8)
Concept
Since \(16=4^2\), the middle term is \(2\cdot4\cdot x=8x\). Exam tip: \(b=2\sqrt{c}\) is useful here.
Why this answer is correct
The correct answer is B. (8). Since \(16=4^2\), the middle term is \(2\cdot4\cdot x=8x\). Exam tip: \(b=2\sqrt{c}\) is useful here.
Exam Tip
\(16=4^2\), इसलिए बीच का पद \(2\cdot4\cdot x=8x\) होगा। परीक्षा में \(b=2\sqrt{c}\) यहां उपयोगी है।
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