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If the sum of the first (r) natural numbers is (153), what is the value of (r+2)?

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Answer and explanation

Correct answer: 19

The sum of the first r natural numbers is \\(\frac{r(r+1)}{2}\\). Thus, \\(\frac{r(r+1)}{2}=153\\), so \\(r(r+1)=306=17\times18\\) and \\(r=17\\). Therefore, \\(r+2=17+2=19\\). Option 18 is only the value of \\(r+1\\), not \\(r+2\\). Exam tip: when a sum is given, first use \\(\frac{n(n+1)}{2}\\) to find n.

Related tags

MathematicsSequences And ProgressionsNatural NumbersSum Of Natural NumbersAlgebra

Frequently asked questions

What is the correct answer to this question?

19

Why is this the correct answer?

The sum of the first r natural numbers is \\(\frac{r(r+1)}{2}\\). Thus, \\(\frac{r(r+1)}{2}=153\\), so \\(r(r+1)=306=17\times18\\) and \\(r=17\\). Therefore, \\(r+2=17+2=19\\). Option 18 is only the value of \\(r+1\\), not \\(r+2\\). Exam tip: when a sum is given, first use \\(\frac{n(n+1)}{2}\\) to find n.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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