If the sum of the first (n) natural numbers is (2145), what is (n)?
Answer and explanation
Correct answer: 65
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Thus, \(\frac{n(n+1)}{2}=2145\), so \(n(n+1)=4290\). Since \(65\times66=4290\), \(n=65\). For \(n=64\), the sum is \(\frac{64\times65}{2}=2080\), not 2145. Exam tip: Set the product of two consecutive numbers equal to \(2S\) to find \(n\) quickly.
Frequently asked questions
What is the correct answer to this question?
65
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Thus, \(\frac{n(n+1)}{2}=2145\), so \(n(n+1)=4290\). Since \(65\times66=4290\), \(n=65\). For \(n=64\), the sum is \(\frac{64\times65}{2}=2080\), not 2145. Exam tip: Set the product of two consecutive numbers equal to \(2S\) to find \(n\) quickly.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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