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If the sum of the first (n) natural numbers is (1540), what is (n)?

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Answer and explanation

Correct answer: 55

The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Thus, \(\frac{n(n+1)}{2}=1540\), so \(n(n+1)=3080\). Since \(55\times56=3080\), \(n=55\). For example, if \(n=54\), the sum is \(\frac{54\times55}{2}=1485\), not 1540. Exam tip: find two consecutive factors of \(2S\) in such questions.

Related tags

Sequences And ProgressionsSum Of Natural NumbersArithmetic SeriesQuadratic EquationClass 9 Mathematics

Frequently asked questions

What is the correct answer to this question?

55

Why is this the correct answer?

The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Thus, \(\frac{n(n+1)}{2}=1540\), so \(n(n+1)=3080\). Since \(55\times56=3080\), \(n=55\). For example, if \(n=54\), the sum is \(\frac{54\times55}{2}=1485\), not 1540. Exam tip: find two consecutive factors of \(2S\) in such questions.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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