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If (S_y=4950), what will be the value of (S_{y+1})?

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Answer and explanation

Correct answer: 5050

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). From \(\frac{y(y+1)}{2}=4950\), we get \(y=99\). Therefore, \(S_{y+1}=S_{100}=S_{99}+100=4950+100=5050\). Getting 5025 would require adding an incorrect next term. Exam tip: use \(S_{n+1}=S_n+(n+1)\) to solve such questions quickly.

Related tags

MathematicsSequences And ProgressionsNatural NumbersSum Of N Natural NumbersSeries

Frequently asked questions

What is the correct answer to this question?

5050

Why is this the correct answer?

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). From \(\frac{y(y+1)}{2}=4950\), we get \(y=99\). Therefore, \(S_{y+1}=S_{100}=S_{99}+100=4950+100=5050\). Getting 5025 would require adding an incorrect next term. Exam tip: use \(S_{n+1}=S_n+(n+1)\) to solve such questions quickly.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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