If (S_n=2701), what will be the value of (S_{n+7}-S_n)?
Answer and explanation
Correct answer: 539
The sum of the first n natural numbers is \(S_n=\frac{n(n+1)}{2}\). Here, \(\frac{n(n+1)}{2}=2701\) gives \(n=73\), since \(S_{73}=\frac{73\times74}{2}=2701\). Therefore, \(S_{n+7}-S_n=S_{80}-S_{73}=74+75+\cdots+80\). This is the sum of 7 consecutive numbers: \(\frac{7(74+80)}{2}=539\). Hence, 539 is correct. A value such as 535 can result from using an incorrect average or number of terms. Exam tip: \(S_{n+k}-S_n\) represents the sum of terms from \(n+1\) to \(n+k\).
Frequently asked questions
What is the correct answer to this question?
539
Why is this the correct answer?
The sum of the first n natural numbers is \(S_n=\frac{n(n+1)}{2}\). Here, \(\frac{n(n+1)}{2}=2701\) gives \(n=73\), since \(S_{73}=\frac{73\times74}{2}=2701\). Therefore, \(S_{n+7}-S_n=S_{80}-S_{73}=74+75+\cdots+80\). This is the sum of 7 consecutive numbers: \(\frac{7(74+80)}{2}=539\). Hence, 539 is correct. A value such as 535 can result from using an incorrect average or number of terms. Exam tip: \(S_{n+k}-S_n\) represents the sum of terms from \(n+1\) to \(n+k\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
