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If Sₙ = 1953, what is the value of S₍ₙ₊₂₎?

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Answer and explanation

Correct answer: 2080

First identify n using Sₙ = n(n + 1)/2. We need n(n + 1)/2 = 1953, so n(n + 1) = 3906. Since 62 × 63 = 3906, n = 62. The requested index is therefore n + 2 = 64. Applying the sum formula gives S₆₄ = 64 × 65/2 = 32 × 65 = 2080. Hence option B is correct. Option A may result from adding only one new term incorrectly, while options C and D usually arise from advancing too far or making an arithmetic error. The essential step is to recover the original index before evaluating the shifted partial sum; the symbol n is not itself equal to 1953.

Related tags

MathematicsSequences-And-ProgressionsShifted-Partial-SumsSum Of First N Natural NumbersSequences And ProgressionsClass 9 Mcq

Frequently asked questions

What is the correct answer to this question?

2080

Why is this the correct answer?

First identify n using Sₙ = n(n + 1)/2. We need n(n + 1)/2 = 1953, so n(n + 1) = 3906. Since 62 × 63 = 3906, n = 62. The requested index is therefore n + 2 = 64. Applying the sum formula gives S₆₄ = 64 × 65/2 = 32 × 65 = 2080. Hence option B is correct. Option A may result from adding only one new term incorrectly, while options C and D usually arise from advancing too far or making an arithmetic error. The essential step is to recover the original index before evaluating the shifted partial sum; the symbol n is not itself equal to 1953.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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