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If r is a rational number, what type of number is \(r+\sqrt{2}\)?यदि r कोई परिमेय संख्या है, तो \(r+\sqrt{2}\) किस प्रकार की संख्या होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Irrational numberअपरिमेय संख्या
\(\sqrt{2}\) is irrational. If \(r+\sqrt{2}\) were rational, subtracting the rational number \(r\) would make \(\sqrt{2}\) rational, which is impossible. Exam tip: rational ± irrational is always irrational.\(\sqrt{2}\) अपरिमेय है। यदि \(r+\sqrt{2}\) परिमेय होता, तो उसमें से परिमेय \(r\) घटाने पर \(\sqrt{2}\) परिमेय हो जाता, जो असंभव है। परीक्षा टिप: परिमेय ± अपरिमेय हमेशा अपरिमेय होता है।
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