यदि (p(x)=x-5\(x^2-6\)-x-7+6x-5+29), तो (p(x)) की डिग्री क्या है?
If (p(x)=x-5\(x^2-6\)-x-7+6x-5+29), what is the degree of (p(x))?
Explanation opens after your attempt
D. (0)
Concept
(x-5\(x^2-6\)=x-7-6x-5). All variable terms cancel and (29) remains, whose degree is (0).
Why this answer is correct
The correct answer is D. (0). (x-5\(x^2-6\)=x-7-6x-5). All variable terms cancel and (29) remains, whose degree is (0).
Exam Tip
(x-5\(x^2-6\)=x-7-6x-5) है। सभी चर पद कट जाते हैं और (29) बचता है जिसकी डिग्री (0) है।
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