यदि (P(x)=\(x^2-3\)\(x^2+3\)-x-4), तो (P(x)) की डिग्री क्या है?
If (P(x)=\(x^2-3\)\(x^2+3\)-x-4), what is the degree of (P(x))?
Explanation opens after your attempt
C. (0)
Concept
(\(x^2-3\)\(x^2+3\)=x-4-9). Subtracting \(x^4\) leaves (-9), whose degree is (0).
Why this answer is correct
The correct answer is C. (0). (\(x^2-3\)\(x^2+3\)=x-4-9). Subtracting \(x^4\) leaves (-9), whose degree is (0).
Exam Tip
(\(x^2-3\)\(x^2+3\)=x-4-9) होता है। \(x^4\) घटाने पर (-9) बचता है जिसकी डिग्री (0) है।
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