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If (J_1=50) and (J_n=J_{n-1}-3(n-1)), what is the value of (J_5)?

Answer and explanation

Correct answer: 20

Apply the recursive rule using the current value of n: J_2=50-3(1)=47, J_3=47-3(2)=41, J_4=41-3(3)=32, and J_5=32-3(4)=20. Therefore, the correct answer is 20. The value 23 may result from subtracting only 3 in the last step instead of 3(n-1), which does not follow the rule. Exam tip: To move from J_1 to J_5, write the four steps for n=2,3,4,5.

Related tags

SequencesProgressionsRecursive RuleClass 9 MathematicsRecurrence RelationSequences And ProgressionsMathematicsClass 9 Mcq

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