If (h_1=3), (h_2=8), and (h_n=2h_{n-1}-h_{n-2}+2n), what is the value of (h_5)?
Answer and explanation
Correct answer: 67
Apply the recursive rule step by step: \(h_3=2(8)-3+2(3)=19\). Next, \(h_4=2(19)-8+2(4)=38\), and \(h_5=2(38)-19+2(5)=67\). Therefore, the correct answer is \(67\). A value such as \(63\) can result from using the wrong value of \(n\) in \(2n\) or mishandling the subtraction of \(h_{n-2}\). Exam tip: substitute the value of \(n\) separately at every step.
Frequently asked questions
What is the correct answer to this question?
67
Why is this the correct answer?
Apply the recursive rule step by step: \(h_3=2(8)-3+2(3)=19\). Next, \(h_4=2(19)-8+2(4)=38\), and \(h_5=2(38)-19+2(5)=67\). Therefore, the correct answer is \(67\). A value such as \(63\) can result from using the wrong value of \(n\) in \(2n\) or mishandling the subtraction of \(h_{n-2}\). Exam tip: substitute the value of \(n\) separately at every step.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Recursive rule.
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