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If C={x∈Z: -5<x≤3}, how many elements does C have?

Answer and explanation

Correct answer: 8

The set-builder condition restricts x to integers strictly greater than −5 and less than or equal to 3. Therefore, the eligible integers are −4, −3, −2, −1, 0, 1, 2, and 3. Counting this list gives 8 elements, so option B is correct. The endpoint −5 is excluded because the inequality is strict, while 3 is included because the inequality is inclusive. Zero must also be counted as an integer.

Related tags

SetsCardinalityIntegersNumber SystemsClass 9 McqMathematics

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