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If (b_n=3b_{n-1}+2) and (b_3=44), what is the value of (b_1)?

Answer and explanation

Correct answer: 4

Using the recursive rule, (b_2=3b_1+2). Therefore, (b_3=3(3b_1+2)+2=9b_1+8). Since (b_3=44), we get (9b_1+8=44), so (9b_1=36) and hence (b_1=4). Substituting 5, 6, or 7 would not give (b_3=44). Exam tip: expand a recursive relation step by step until it connects to the required term.

Related tags

Sequences And ProgressionsRecursive SequencesRecursive RuleAlgebraic SubstitutionClass 9 MathematicsMathematicsClass 9 Mcq

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