यदि समांतर श्रेणी में \(a_6=29\) और \(a_{11}=64\) है, तो \(a_{15}\) क्या होगा?
If an arithmetic progression has \(a_6=29\) and \(a_{11}=64\), what is \(a_{15}\)?
Explanation opens after your attempt
B. (92)
Concept
The increase over five gaps is (35), so (d=7) and (a_{15}=64+4(7)=92). First find (d), then move forward.
Why this answer is correct
The correct answer is B. (92). The increase over five gaps is (35), so (d=7) and (a_{15}=64+4(7)=92). First find (d), then move forward.
Exam Tip
पाँच अंतरों में वृद्धि (35) है, इसलिए (d=7) और (a_{15}=64+4(7)=92)। पहले (d) निकालें फिर आगे बढ़ें।
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