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If (a_n=n^2+7n-8), what is the value of (a_9-a_4)?

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Answer and explanation

Correct answer: 100

Given \(a_n=n^2+7n-8\), \(a_9=9^2+7(9)-8=81+63-8=136\) and \(a_4=4^2+7(4)-8=16+28-8=36\). Hence, \(a_9-a_4=136-36=100\). A value such as 104 can result from substituting an incorrect value for one of the terms. Exam tip: calculate each required term separately before finding their difference.

Related tags

SequencesProgressionsNth TermQuadratic SequenceSubstitution

Frequently asked questions

What is the correct answer to this question?

100

Why is this the correct answer?

Given \(a_n=n^2+7n-8\), \(a_9=9^2+7(9)-8=81+63-8=136\) and \(a_4=4^2+7(4)-8=16+28-8=36\). Hence, \(a_9-a_4=136-36=100\). A value such as 104 can result from substituting an incorrect value for one of the terms. Exam tip: calculate each required term separately before finding their difference.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.

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