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If \(a_n=\frac{2n+1}{3}\), what is the value of \(a_8\)?

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Answer and explanation

Correct answer: \(\frac{17}{3}\)

Substitute \(n=8\) in \(a_n=\frac{2n+1}{3}\): \(a_8=\frac{2(8)+1}{3}=\frac{16+1}{3}=\frac{17}{3}\). Hence, \(\frac{17}{3}\) is correct. The value \(\frac{16}{3}\) would result from incorrectly omitting the \(+1\) in the numerator. Exam tip: substitute the given value of \(n\) into every part of the formula before simplifying.

Related tags

Sequences And ProgressionsNth TermAlgebraic SequenceClass 9 MathematicsSubstitution

Frequently asked questions

What is the correct answer to this question?

\(\frac{17}{3}\)

Why is this the correct answer?

Substitute \(n=8\) in \(a_n=\frac{2n+1}{3}\): \(a_8=\frac{2(8)+1}{3}=\frac{16+1}{3}=\frac{17}{3}\). Hence, \(\frac{17}{3}\) is correct. The value \(\frac{16}{3}\) would result from incorrectly omitting the \(+1\) in the numerator. Exam tip: substitute the given value of \(n\) into every part of the formula before simplifying.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.

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