If \(a_n=5\cdot2^{n-1}+1\), what is the value of \(a_6\)?
Answer and explanation
Correct answer: 161
Putting \(n=6\), \(a_6=5\cdot2^{6-1}+1=5\cdot2^5+1=5\cdot32+1=161\). Therefore, 161 is correct. Option 160 would result from incorrectly omitting the final \(+1\). Exam tip: Substitute the value of \(n\) into the exponent \(n-1\) first, then calculate step by step.
Frequently asked questions
What is the correct answer to this question?
161
Why is this the correct answer?
Putting \(n=6\), \(a_6=5\cdot2^{6-1}+1=5\cdot2^5+1=5\cdot32+1=161\). Therefore, 161 is correct. Option 160 would result from incorrectly omitting the final \(+1\). Exam tip: Substitute the value of \(n\) into the exponent \(n-1\) first, then calculate step by step.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.
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