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If (a_n=2n^2+9n-11), what is the value of (a_{10}-a_4)?

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Answer and explanation

Correct answer: 222

Given \(a_n=2n^2+9n-11\), \(a_{10}=2(10)^2+9(10)-11=279\) and \(a_4=2(4)^2+9(4)-11=57\). Therefore, \(a_{10}-a_4=279-57=222\). The value 204 results from incorrectly calculating \(a_4\) as 75. Exam tip: substitute each value of \(n\) separately before finding the difference.

Related tags

Sequences And ProgressionsNth TermQuadratic SequenceSubstitutionAlgebra

Frequently asked questions

What is the correct answer to this question?

222

Why is this the correct answer?

Given \(a_n=2n^2+9n-11\), \(a_{10}=2(10)^2+9(10)-11=279\) and \(a_4=2(4)^2+9(4)-11=57\). Therefore, \(a_{10}-a_4=279-57=222\). The value 204 results from incorrectly calculating \(a_4\) as 75. Exam tip: substitute each value of \(n\) separately before finding the difference.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.

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