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If (a_n=2n^2+3n-4), what is the value of (a_8-a_5)?

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Answer and explanation

Correct answer: 87

Given \(a_n=2n^2+3n-4\), \(a_8=2(8)^2+3(8)-4=128+24-4=148\) and \(a_5=2(5)^2+3(5)-4=50+15-4=61\). Therefore, \(a_8-a_5=148-61=87\). Option 84 may seem close, but it does not result from evaluating both terms correctly. Exam tip: calculate each required term separately before finding their difference.

Related tags

SequencesProgressionsNth TermQuadratic SequenceSubstitution

Frequently asked questions

What is the correct answer to this question?

87

Why is this the correct answer?

Given \(a_n=2n^2+3n-4\), \(a_8=2(8)^2+3(8)-4=128+24-4=148\) and \(a_5=2(5)^2+3(5)-4=50+15-4=61\). Therefore, \(a_8-a_5=148-61=87\). Option 84 may seem close, but it does not result from evaluating both terms correctly. Exam tip: calculate each required term separately before finding their difference.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.

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