यदि \(a_1=9\) और \(a_{n+1}=a_n+8\) है तो \(a_{12}\) क्या होगा?
If \(a_1=9\) and \(a_{n+1}=a_n+8\), what is \(a_{12}\)?
Explanation opens after your attempt
C. (97)
Concept
For \(a_{12}\), (8) is added (11) times, so (9+88=97). Exam tip: the rule is applied one less time than the term number.
Why this answer is correct
The correct answer is C. (97). For \(a_{12}\), (8) is added (11) times, so (9+88=97). Exam tip: the rule is applied one less time than the term number.
Exam Tip
\(a_{12}\) के लिए (8) को (11) बार जोड़ा जाता है इसलिए (9+88=97) है। पद संख्या से एक कम बार नियम लगता है।
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