यदि \(a_1=9\) और \(a_{n+1}=a_n+8\) है तो \(a_{12}\) क्या होगा?

If \(a_1=9\) and \(a_{n+1}=a_n+8\), what is \(a_{12}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (97)

Step 1

Concept

For \(a_{12}\), (8) is added (11) times, so (9+88=97). Exam tip: the rule is applied one less time than the term number.

Step 2

Why this answer is correct

The correct answer is C. (97). For \(a_{12}\), (8) is added (11) times, so (9+88=97). Exam tip: the rule is applied one less time than the term number.

Step 3

Exam Tip

\(a_{12}\) के लिए (8) को (11) बार जोड़ा जाता है इसलिए (9+88=97) है। पद संख्या से एक कम बार नियम लगता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=9\) और \(a_{n+1}=a_n+8\) है तो \(a_{12}\) क्या होगा? / If \(a_1=9\) and \(a_{n+1}=a_n+8\), what is \(a_{12}\)?

Correct Answer: C. (97). Explanation: \(a_{12}\) के लिए (8) को (11) बार जोड़ा जाता है इसलिए (9+88=97) है। पद संख्या से एक कम बार नियम लगता है। / For \(a_{12}\), (8) is added (11) times, so (9+88=97). Exam tip: the rule is applied one less time than the term number.

Which concept should I revise for this Mathematics MCQ?

For \(a_{12}\), (8) is added (11) times, so (9+88=97). Exam tip: the rule is applied one less time than the term number.

What exam hint can help solve this Mathematics question?

\(a_{12}\) के लिए (8) को (11) बार जोड़ा जाता है इसलिए (9+88=97) है। पद संख्या से एक कम बार नियम लगता है।