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If (a_1=4) and (a_{n+1}=a_n^2), what is (a_2)?

Answer and explanation

Correct answer: 16

Put \(n=1\) in the recursive rule: \(a_2=a_1^2=4^2=16\). Therefore, 16 is correct. The value 8 would be obtained by doubling 4, but the rule requires squaring the previous term. Exam tip: to find \(a_{n+1}\), apply the given rule directly to \(a_n\).

Related tags

Recursive SequencesRecursive RuleSquaringSequences And ProgressionsClass 9 MathematicsMathematicsClass 9 Mcq

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