How much is the sum of the first (58) natural numbers?
Answer and explanation
Correct answer: 1711
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Here, \(n=58\), so \(\frac{58\times59}{2}=29\times59=1711\). Therefore, 1711 is correct. A value such as 1701 can result from an arithmetic error. Exam tip: When \(n\) is even, divide it by 2 first to simplify the calculation.
Frequently asked questions
What is the correct answer to this question?
1711
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Here, \(n=58\), so \(\frac{58\times59}{2}=29\times59=1711\). Therefore, 1711 is correct. A value such as 1701 can result from an arithmetic error. Exam tip: When \(n\) is even, divide it by 2 first to simplify the calculation.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
