How much is the sum of the first (49) natural numbers?
Answer and explanation
Correct answer: 1225
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Putting \(n=49\), we get \(\frac{49\times 50}{2}=49\times 25=1225\). Hence, 1225 is the correct answer. A value such as 1215 may result from an incorrect multiplication or addition. Exam tip: use \(\frac{n(n+1)}{2}\) for the sum from \(1\) to \(n\).
Frequently asked questions
What is the correct answer to this question?
1225
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Putting \(n=49\), we get \(\frac{49\times 50}{2}=49\times 25=1225\). Hence, 1225 is the correct answer. A value such as 1215 may result from an incorrect multiplication or addition. Exam tip: use \(\frac{n(n+1)}{2}\) for the sum from \(1\) to \(n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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