किस मान पर (\(b^2-25\)x-11) रेखीय बहुपद नहीं रहेगा?
For which value will (\(b^2-25\)x-11) not remain a linear polynomial?
Explanation opens after your attempt
Correct Answer
B. (b=5) या (b=-5)(b=5) or (b=-5)
Concept
For it not to be linear, the coefficient of (x) must be (0). From \(b^2-25=0\), \(b=\pm5\).
Why this answer is correct
The correct answer is B. (b=5) या (b=-5) / (b=5) or (b=-5). For it not to be linear, the coefficient of (x) must be (0). From \(b^2-25=0\), \(b=\pm5\).
Exam Tip
रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(b^2-25=0\) से \(b=\pm5\) मिलता है।
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