Find the value of ( 103^2 ) using an identity.
Answer and explanation
Correct answer: 10609
Using \((a+b)^2=a^2+2ab+b^2\), take \(a=100\) and \(b=3\). Then \(103^2=(100+3)^2=10000+600+9=10609\). Hence, 10609 is correct. The option 10600 misses the \(3^2=9\) term. Exam tip: while applying the square identity, include both the middle term \(2ab\) and the final term \(b^2\).
Frequently asked questions
What is the correct answer to this question?
10609
Why is this the correct answer?
Using \((a+b)^2=a^2+2ab+b^2\), take \(a=100\) and \(b=3\). Then \(103^2=(100+3)^2=10000+600+9=10609\). Hence, 10609 is correct. The option 10600 misses the \(3^2=9\) term. Exam tip: while applying the square identity, include both the middle term \(2ab\) and the final term \(b^2\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Algebraic identities.
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