Find the sum of the first (60) natural numbers.
Answer and explanation
Correct answer: 1830
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=60\), we get \(\frac{60\times61}{2}=30\times61=1830\). A value such as \(1800\) may result from incorrectly using \(60\times60/2\), but the formula must include \(n+1=61\). Exam tip: for consecutive natural numbers starting from 1, use \(\frac{n(n+1)}{2}\).
Frequently asked questions
What is the correct answer to this question?
1830
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=60\), we get \(\frac{60\times61}{2}=30\times61=1830\). A value such as \(1800\) may result from incorrectly using \(60\times60/2\), but the formula must include \(n+1=61\). Exam tip: for consecutive natural numbers starting from 1, use \(\frac{n(n+1)}{2}\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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