Find the sum of the first (45) natural numbers.
Answer and explanation
Correct answer: 1035
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=45\), we get \(\frac{45\times46}{2}=45\times23=1035\). Hence, 1035 is correct. An option such as 1025 may result from an incorrect addition or multiplication. Exam tip: in this formula, always use \(n+1\) along with \(n\).
Frequently asked questions
What is the correct answer to this question?
1035
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=45\), we get \(\frac{45\times46}{2}=45\times23=1035\). Hence, 1035 is correct. An option such as 1025 may result from an incorrect addition or multiplication. Exam tip: in this formula, always use \(n+1\) along with \(n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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