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A student added numbers from (1) to (175) and then subtracted the sum from (1) to (125). What will be the result?

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Answer and explanation

Correct answer: 7525

Let the sum of the first n natural numbers be \(S_n=\frac{n(n+1)}{2}\). Therefore, the required result is \(S_{175}-S_{125}=\frac{175\times176}{2}-\frac{125\times126}{2}=15400-7875=7525\). It is also the direct sum of the numbers from 126 to 175. An option such as 7475 results from an error in evaluating a sum or subtraction. Exam tip: the difference of two sums with the same starting term equals the sum of the remaining consecutive terms.

Tags

sequences and progressionssum of natural numbersarithmetic seriesconsecutive integersclass 9 mathematics

Frequently asked questions

What is the correct answer to this question?

7525

Why is this the correct answer?

Let the sum of the first n natural numbers be \(S_n=\frac{n(n+1)}{2}\). Therefore, the required result is \(S_{175}-S_{125}=\frac{175\times176}{2}-\frac{125\times126}{2}=15400-7875=7525\). It is also the direct sum of the numbers from 126 to 175. An option such as 7475 results from an error in evaluating a sum or subtraction. Exam tip: the difference of two sums with the same starting term equals the sum of the remaining consecutive terms.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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