A student added numbers from (1) to (120) and then subtracted the sum from (1) to (80). What will be the result?
Answer and explanation
Correct answer: 4020
The sum of the first 120 natural numbers is \(\frac{120\times121}{2}=7260\), and the sum of the first 80 natural numbers is \(\frac{80\times81}{2}=3240\). Therefore, the required result is \(7260-3240=4020\). This is also the sum of the numbers from 81 to 120. An option such as 4040 can result from an arithmetic error in subtraction. Exam tip: use \(S_n=\frac{n(n+1)}{2}\) and subtract the two sums carefully.
Frequently asked questions
What is the correct answer to this question?
4020
Why is this the correct answer?
The sum of the first 120 natural numbers is \(\frac{120\times121}{2}=7260\), and the sum of the first 80 natural numbers is \(\frac{80\times81}{2}=3240\). Therefore, the required result is \(7260-3240=4020\). This is also the sum of the numbers from 81 to 120. An option such as 4040 can result from an arithmetic error in subtraction. Exam tip: use \(S_n=\frac{n(n+1)}{2}\) and subtract the two sums carefully.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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