A student added all numbers from (1) to (37). What will be the result?
Answer and explanation
Correct answer: 703
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Here, \(n=37\), so the sum is \(\frac{37\times38}{2}=37\times19=703\). A value such as 693 can result from an arithmetic error while multiplying or dividing. Exam tip: for consecutive numbers from 1 to \(n\), apply \(\frac{n(n+1)}{2}\) directly.
Frequently asked questions
What is the correct answer to this question?
703
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Here, \(n=37\), so the sum is \(\frac{37\times38}{2}=37\times19=703\). A value such as 693 can result from an arithmetic error while multiplying or dividing. Exam tip: for consecutive numbers from 1 to \(n\), apply \(\frac{n(n+1)}{2}\) directly.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
